The cost (c) to hire a dog trainer is varies directly with the amount of time (h) in hours spent training the dog.
Part A
Write an equation to represent the proportional relationship between c and h using the information given.
c =
Part B
Sue spent $660 on 12 hours of obedience training for her dog Muffin. Jon wants to use the same dog trainer for his dog Tex, but he only has $440 to spend. How many hours of training can he get for Tex? Explain your reasoning.
I don't want the answer just how to solve the equations....Im stuck on this problem. If I can get how to solve Part a I can probably get the rest. Thanks!! Equations are trying me today!!
I need help please
So what’s the answer?
really ''-bots
I think the equation would be c = kh because k equals the constant of proportionality. Uhm.. That’s all I have. Bye
ion know my teacher just gone have to give me a 0 cuz what is this
Part A:
Since the cost (c) varies directly with the amount of time (h), we can write the equation as:
c = kh
where k represents the constant of variation.
Part B:
To determine how many hours of training Jon can get for Tex with his budget of $440, we need to find the value of h when c = $440.
Using the equation from Part A, we have:
440 = kh
To isolate h, we need to divide both sides of the equation by k:
440/k = h
Now, we need to find the value of k using the information given in the problem.
We are told that Sue spent $660 on 12 hours of training, so we can use these values to find k.
Using the equation from Part A:
660 = k * 12
To solve for k, divide both sides of the equation by 12:
k = 660/12
Simplifying:
k = 55
Now we can substitute the value of k into the equation we found earlier:
440/55 = h
Simplifying further:
8 = h
Therefore, Jon can get 8 hours of training for Tex with his budget of $440.
c = kh
for some constant value of k.
that's what "varies directly" means...
Now use the numbers they gave you to find k, so you can then find c and h as needed.