chemistry

determine the oxidation number of each of the atoms of the following compounds:
1) H2S03
2) 0H^-
3) HPO4^2-

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  1. Here is a very good site on determining oxidations numbers.
    https://www.chemteam.info/Redox/Redox-Rules.html

  2. can someone help me do the first one.
    my answer is:
    H2 = +1
    S = +4
    O3 = -2

    Is my answer correct?

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  3. Yes, you are correct on all. I would have liked it better if you had written EACH after H and O: like this:

    H = +1 each
    S = +4
    O = -2 each
    I shall be happy to check the others if you wish to post.Here is how I do them.
    H is +1 almost always. ONly in hydride is it -1. Generally, if H is listed first, as in H2S, H2O, H2SO4, etc, it is +1. Listed second as in NaH, LiH etc it is a hydride and is -1.
    Oxygen is almost always -2 except in peroxides where it is -1. But is is -2 here. Remember that the compound is zero charge so everything must add to zero.
    So H is +1 each x 2 = +2.
    O is -2 each x 3 = -6.
    Then +2 + (S) -6 = 0
    What is S? It is S = -2+6 = +4
    You did great.

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