Day
Sunday 49
Monday 55
Tuesday 52
Wednesday 46
Thursday 47
Friday 42
Saturday 38
Temperature (degrees F)
Julia measured the high temperature in her town for one week. Using the chart above, find the mean absolute deviation for the high temperatures. Round your answer to the nearest tenth.
Be sure to show your work for finding:
the mean of the set of data
the distance of each number from the mean
the mean absolute deviation
HELP FAST
thats no help whatsoever oobleck, youre name isn't even ms/mr.oobleck
To find the mean absolute deviation for the high temperatures, we need to follow these steps:
1. Find the mean of the set of data:
To find the mean, we sum up all the temperatures and then divide by the number of days in the week.
Mean = (49 + 55 + 52 + 46 + 47 + 42 + 38) / 7
Mean = 329 / 7
Mean = 47
So, the mean of the set of data is 47.
2. Find the distance of each number from the mean:
To find the distance, we subtract the mean from each temperature. The absolute value is used to ensure we only have positive values.
Distances: |49 - 47|, |55 - 47|, |52 - 47|, |46 - 47|, |47 - 47|, |42 - 47|, |38 - 47|
Distances: 2, 8, 5, 1, 0, 5, 9
3. Find the mean absolute deviation:
To find the mean absolute deviation, we have to calculate the mean of the distances.
Mean absolute deviation = (2 + 8 + 5 + 1 + 0 + 5 + 9) / 7
Mean absolute deviation = 30 / 7
Rounding the answer to the nearest tenth:
Mean absolute deviation≈ 4.3
Therefore, the mean absolute deviation for the high temperatures is approximately 4.3.