Ten plus eight times a number a equals eleven times another number d minus six solve for a
My solution
8a+10=11d-6
a=11d/8-2
Please check if I am correct.
what was the equation you were given at first?
but if that was the equation you were given first then youre wrong if you're solving for A. It would be:
8a−10 11d-6
+10 = 11d−6+10
8a=11d+4
Then divide both sides by 8 and you have
a= 11/8d + 1/2
Edited: a=11d-2 divided by -2
Oh gosh again typed wrong
a=11d-2 divided by 8
To solve the equation 10 + 8a = 11d - 6 for 'a', you need to isolate 'a' on one side of the equation. Here's the correct process:
Start with the equation: 10 + 8a = 11d - 6
First, remove the constant term (-6) from the right side:
8a = 11d - 6 - 10
8a = 11d - 16
Next, divide both sides of the equation by 8 to solve for 'a':
a = (11d - 16) / 8
Therefore, the correct solution is:
a = (11d - 16) / 8
Your solution, a = 11d/8 - 2, is incorrect.