Calculate the specific heat capacity of the materials for which the heat supply mass,and temperature rises are given below(i)2.5*10^4j,0.3kg,2k^-1
(ii)8*4^3j,500g from30'c to 50'c
(iii)9.45*10^3g ,150g from15'c to 45'c
Answer
To calculate the specific heat capacity (symbolized by c) of a material, you can use the formula:
Q = mcΔT
Where:
Q is the heat supplied (in joules),
m is the mass of the material (in kilograms),
c is the specific heat capacity of the material (in J/kg·K),
ΔT is the change in temperature (in Kelvin).
Now let's calculate the specific heat capacities for the given scenarios:
(i) Q = 2.5 * 10^4 J, m = 0.3 kg, ΔT = 2 K
Using the formula Q = mcΔT, we can rearrange it to solve for c:
c = Q / (m * ΔT)
Substituting the given values:
c = (2.5 * 10^4 J) / (0.3 kg * 2 K)
c ≈ 4.17 × 10^4 J/kg·K
(ii) Q = 8 * 4^3 J, m = 500 g = 0.5 kg, ΔT = (50 - 30) K = 20 K
Using the formula, we have:
c = Q / (m * ΔT)
Substituting the values:
c = (8 * 4^3 J) / (0.5 kg * 20 K)
c ≈ 16 J/kg·K
(iii) Q = 9.45 * 10^3 J, m = 150 g = 0.15 kg, ΔT = (45 - 15) K = 30 K
Using the formula, we can calculate c:
c = Q / (m * ΔT)
Substituting the values:
c = (9.45 * 10^3 J) / (0.15 kg * 30 K)
c ≈ 1.32 × 10^3 J/kg·K
Therefore, the specific heat capacities for the given scenarios are:
(i) c ≈ 4.17 × 10^4 J/kg·K
(ii) c ≈ 16 J/kg·K
(iii) c ≈ 1.32 × 10^3 J/kg·K