Major car park has y levels. Each level has n rows and each row has n spaces. The charge for each space is $x per day. The maximum total revenue for each day is therefore...
Could you answer this question?
Major car park has 3 levels. Each level has 6 rows and each row has 10 spaces. The charge for each space is $5 per day. The maximum total revenue for each day is therefore...
What did you do to get $900 ?
Now repeat the same for the given problem.
So basically... there are different ways to answer this problem? Like... it's an open-ended question?
Huh?
If you have y levels, each level has n rows, and each row has n spaces. The charge for each space is $x per day. The maximum total revenue for each day is
$ynnx or $(y)(n^2)(x) or $n^2 xy
In my actual example, did you not notice that I multiplied the data numbers to get the cost of $900
that is, (3)(6)(10)(5) = 900
I just understood that a day ago... thanks to the example you gave me
To calculate the maximum total revenue for each day, we need to know the values of y, n, and x.
Let's break it down step by step:
1. Determine the number of spaces in each level. Since each row has n spaces, and there are n rows per level, the total number of spaces per level is n * n = n^2.
2. Calculate the total number of spaces in the car park. Since there are y levels and each level has n^2 spaces, the total number of spaces in the car park is y * n^2.
3. Now, we can calculate the maximum total revenue for each day. The revenue for each space per day is $x. Therefore, the maximum total revenue is the product of the number of spaces and the charge per space: y * n^2 * x.
So, the maximum total revenue for each day in the car park is y * n^2 * x dollars.