James is two years younger than twice his sister Kate’s Age. Together their ages add up to 19. What is each of their ages?
j = 2k-2
j+k = 19
now just crank it out
Kate is X yrs. old.
James 2x-2 yrs. old.
x + (2x-2) = 19.
X = 7.
2z-2 = ?
To solve this problem, let's assign variables to James and Kate's ages. Let's say James's age is "J" and Kate's age is "K".
According to the given information, we can form two equations:
1. James is two years younger than twice Kate's age:
J = 2K - 2
2. The sum of their ages is 19:
J + K = 19
Now we have a system of two equations with two variables. We can solve this system to find the values of J and K.
Using equation 1, we have J = 2K - 2. We can substitute this into equation 2:
(2K - 2) + K = 19
Simplifying the equation:
3K - 2 = 19
3K = 21
K = 7
Now we know Kate's age K is 7. To find James's age J, we substitute the value of K into equation 1:
J = 2K - 2 = 2(7) - 2 = 14 - 2 = 12
Therefore, Kate's age is 7 and James's age is 12.