How many square tiles each of side 8cm are needed to tile a floor 22m 40cm long by 12m 80cm wide?
You have the room width and length, in cm.
Since each tile is 8x8 cm, then the room size measured in tiles, is
(2240/8)(1280/8) = 280x160 = 44800 tiles
Af = L*W = 22.4 * 12.8 = 286.72 m^2. = Area of the floor.
At = L*W = 0.08 * 0.08 = 0.0064 m^2 = Area of each tile.
Af/At = 286.72/0.0064 = 44,800 tiles.
To find the number of square tiles needed to tile the given floor, we need to calculate the area of the floor and divide it by the area of a single tile.
Step 1: Convert the dimensions into the same units.
The length of the floor is 22m 40cm, which can be converted to cm as 2240cm.
Similarly, the width of the floor is 12m 80cm, which can be converted to cm as 1280cm.
Step 2: Calculate the area of the floor.
The area of the floor can be calculated by multiplying the length and width:
Area = Length × Width
Area = 2240cm × 1280cm
Step 3: Convert the area of the floor into the area of a single tile.
Since the side length of each tile is 8cm, the area of an individual tile is 8cm × 8cm.
Step 4: Divide the area of the floor by the area of a single tile.
Number of tiles needed = Area of the floor ÷ Area of a single tile
Now, let's perform the calculations:
Area of the floor = 2240cm × 1280cm
= 2867200cm²
Area of a single tile = 8cm × 8cm
= 64cm²
Number of tiles needed = 2867200cm² ÷ 64cm²
= 44800
Therefore, you would need 44,800 square tiles, each with a side length of 8cm, to tile the given floor.