Balance the following equations if the reactions will occur.
gold + oxygen
Au + O2 --> ???????
barium + oxygen
Ba + O2 --> ???
bismuth + oxygen -->
Bi + O2 --> ???
help please. keep in mind this is single replacement
None of these are single replacement. All of them, if they react, are synthesis.
Ahh ok. I guess the worksheet tried to trick me. Thanks alot!
To balance the given equations, we need to ensure that the number of each type of atom is the same on both sides of the equation. Here's how you can balance each equation:
1. gold + oxygen (Au + O2):
To balance this equation, we need to put a coefficient in front of each reactant and product to ensure that the number of each type of atom is balanced. Since there is only one gold atom on the left side, we need to put a "2" in front of the Au:
2Au + O2 -->
Now, let's balance the oxygen atoms. There are two oxygen atoms on the right side, so we need to put a "2" in front of the O2:
2Au + 2O2 -->
The equation is now balanced.
2. barium + oxygen (Ba + O2):
Similarly, let's put a coefficient in front of each reactant and product to balance the equation. Since there is only one barium atom on the left side, put a "1" in front of the Ba:
Ba + O2 -->
Balancing the oxygen atoms, there are two oxygen atoms on the right side, so put a "2" in front of the O2:
Ba + 2O2 -->
The equation is now balanced.
3. bismuth + oxygen (Bi + O2):
Once again, put a coefficient in front of each reactant and product to balance the equation. Since there is one bismuth atom on the left side, put a "1" in front of the Bi:
Bi + O2 -->
For balancing the oxygen atoms, there are two oxygen atoms on the right side, so put a "2" in front of the O2:
Bi + 2O2 -->
The equation is now balanced.
Here are the balanced equations:
1. 2Au + 2O2 -->
2. Ba + 2O2 -->
3. Bi + 2O2 -->