if the maximum voltage across a 100 ohm resistor is 20. then the maximum power it can dissipate is?
P is proportional to E^2
so, max E means max P (for a given R)
Pmax = E^2/R = 20^2/100 = ___Watts.
To find the maximum power dissipated by a resistor, you can use Ohm's Law and the power formula.
First, let's review Ohm's Law, which states that the voltage across a resistor is equal to the current flowing through it multiplied by its resistance:
V = I * R
Where:
V = Voltage across the resistor
I = Current flowing through the resistor
R = Resistance of the resistor
We are given the resistance (R) as 100 ohms and the maximum voltage (V) as 20 volts in this case.
Next, we can calculate the maximum current (I) using Ohm's Law:
I = V / R
Plugging in the values:
I = 20 V / 100 Ω
I = 0.2 A
Now that we know the maximum current, we can calculate the maximum power (P) dissipated by the resistor using the power formula:
P = I^2 * R
Plugging in the values:
P = (0.2 A)^2 * 100 Ω
P = 0.04 A^2 * 100 Ω
P = 4 W
Therefore, the maximum power that can be dissipated by the 100 ohm resistor is 4 watts.