r=.10,m=1.6*10^-27,f=2.5*10^-12, use formula f=mrww,calculate w?
Assume you are doing centripetal force:
F = m Ac = m R omega^2
2.5*10^-12 Newtons = 1.6*10^-27 Kg * 0.10 meters * omega^2 radians^2/Second^2
so
omega^2 = (2.5/0.16) 10^15
I guess maybe that is a proton?
To calculate the value of w using the formula f = mrw^2, where r = 0.10, m = 1.6 * 10^-27, and f = 2.5 * 10^-12, we will rearrange the formula and solve for w.
Step 1: Rearrange the formula:
f = mrw^2
Divide both sides of the equation by mr:
f / (mr) = w^2
Step 2: Substitute the given values:
f = 2.5 * 10^-12
m = 1.6 * 10^-27
r = 0.10
(w^2) = (2.5 * 10^-12) / (1.6 * 10^-27 * 0.10)
Step 3: Simplify the expression:
Dividing the numerator and denominator separately, we can rewrite the equation as:
(w^2) = (2.5 * 10^-12) / (1.6 * 10^-28)
Now combine the coefficients and subtract the exponents of 10:
(w^2) = (2.5 / 1.6) * (10^-12 / 10^-28)
(w^2) = 1.5625 * (10^28 / 10^12)
(w^2) = 1.5625 * 10^16
Step 4: Take the square root of both sides to solve for w:
w = √(1.5625 * 10^16)
w ≈ 1.25 * 10^8
Therefore, the value of w is approximately 1.25 * 10^8.