32g of anhydrous copper(ii)tetraoxosulphate(iv) dissolves in 1Dm3 of water generated 13.0KJ of heat,The heat of solution is
My assumption is you mean CuSO4 but you have not named it correctly by IUPAC rules.
mols CuSO4 = grams/molar mass = 32/approx 159 = approx 0.2 but you need to recalculate ALL of these values. My numbers are just estimates.
dHsoln = kJ/mol = 13.0 kJ/0.2 mol = approx ?
Note: Since heat is generated dHsoln will be negative.
To find the heat of solution, we need to calculate the amount of heat transferred per gram of the solute.
First, we need to convert the mass of anhydrous copper(II) tetraoxosulphate(IV) from grams to moles. The molar mass of anhydrous copper(II) tetraoxosulphate(IV) can be calculated by adding up the atomic masses of each element:
Cu = 63.55 g/mol
O = 16.00 g/mol
S = 32.07 g/mol
Molar mass of CuSO4 = (63.55) + (4 × 16.00) + 32.07 = 159.61 g/mol
Now we can calculate the number of moles:
moles = mass / molar mass
moles = 32 g / 159.61 g/mol
moles = 0.2006 mol
Next, we need to calculate the heat of solution per mole:
heat of solution = heat generated / moles
heat of solution = 13.0 kJ / 0.2006 mol
heat of solution = 64.88 kJ/mol
Therefore, the heat of solution for anhydrous copper(II) tetraoxosulphate(IV) is 64.88 kJ/mol.
To calculate the heat of solution, you need to use the formula:
Heat of solution = (heat released or absorbed) / (mass of solute)
In this case, the heat released during the dissolution is 13.0 KJ, and the mass of the solute (anhydrous copper(ii)tetraoxosulphate(iv)) is 32 g.
Therefore, the heat of solution can be calculated as follows:
Heat of solution = 13.0 KJ / 32 g
To calculate the heat of solution, you need to convert the given mass of solute from grams to moles. To do this, you need to find the molar mass of anhydrous copper(ii)tetraoxosulphate(iv).
Molar mass of copper(ii)tetraoxosulphate(iv) (CuSO4) = atomic mass of Cu + 4 x (atomic mass of S + 4 x atomic mass of O)
The atomic masses of Cu, S, and O are:
Atomic mass of Cu = 63.55 g/mol
Atomic mass of S = 32.07 g/mol
Atomic mass of O = 16.00 g/mol
Molar mass of CuSO4 = 63.55 g/mol + 4 x (32.07 g/mol + 4 x 16.00 g/mol)
Once you have the molar mass of CuSO4, you can calculate the moles of copper(ii)tetraoxosulphate(iv) using the formula:
moles = mass / molar mass
Now, substitute the mass (32 g) and molar mass of CuSO4 into the formula to calculate the moles.
Finally, substitute the moles of copper(ii)tetraoxosulphate(iv) into the formula for the heat of solution to get your answer:
Heat of solution = 13.0 KJ / moles of CuSO4