A boy is 10years old and his mother is 37years old. In how many years time will the mother be twice as old as her son
37 + x = 2(10+x)
37 + x = 20 + 2 x
x = 37-20= 17
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Yes
To find out in how many years the mother will be twice as old as her son, we need to set up an equation.
Let's assume that after a certain number of years, denoted by 'x', the son's age will be (10 + x) and the mother's age will be (37 + x).
According to the problem, we want the mother's age to be twice as old as her son's age. So we can set up the equation:
37 + x = 2(10 + x)
Now, let's solve the equation to find the value of x.
37 + x = 20 + 2x
Rearranging the equation:
x - 2x = 20 - 37
Simplifying:
-x = -17
Multiplying both sides by -1 to isolate x:
x = 17
Therefore, it will take 17 years for the mother to be twice as old as her son.