mark is 10years older than his brother .in four years he will be twice as ld as his brother.find the present age
M = Mark´s present age
B = Brother´s present age
Mark is 10 years older than his brother mean:
M = B + 10
After four years Mark will be M + 4 yrs old and brother wil bee B + 4 yrs old.
In four years he will be twice as old as his brother mean:
( M + 4 ) / ( B + 4 ) = 2
Now you must solve system:
M = B + 10
( M + 4 ) / ( B + 4 ) = 2
Try that.
The solution is:
M = 16 , B = 6
bro. is X yrs. old,
Mark is x+10 yrs. old.
In 4 yrs. :
(x+10) + 4 = 2(x+4),
x + 14 = 2x + 8,
X = 6 = Mark's bro. present age.
x+10 = 6 + 10 = 16 = Mark's present age.
;
A car traveling at 50km hrs it decelerate at a uniform rate of 5kms the time taken is 32km hrs
To find the present age of Mark and his brother, we can set up a system of equations based on the given information.
Let's say Mark's current age is M, and his brother's current age is B.
According to the information given, Mark is 10 years older than his brother. This can be expressed as:
M = B + 10 (Equation 1)
In four years, Mark will be twice as old as his brother. We can represent this as:
M + 4 = 2(B + 4) (Equation 2)
Now, let's solve this system of equations to find the present ages of Mark and his brother.
Substitute Equation 1 into Equation 2:
(B + 10) + 4 = 2(B + 4)
Simplify:
B + 14 = 2B + 8
Rearrange:
2B - B = 14 - 8
B = 6
Substitute the value of B into Equation 1:
M = 6 + 10
M = 16
Therefore, Mark's present age is 16 years, and his brother's present age is 6 years.