If f(x)=x^4+6, g(x)=x-2 and h(x)=sqrt(x), then f(g(h(x)))=
Please help ASAP I really confused with this math problem!!!
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just plug and chug.
g(x) = x-2
so, g(h(x)) = h(x)-2 = √x - 2
f(g(h(x))) = g(h(x))^4+6 = (√x - 2)^4 + 6
The x is just a place holder. You can replace it with whatever you want.
Sure! I can help you with this math problem.
To find the value of f(g(h(x))), we need to follow these steps:
Step 1: Find the value of h(x)
Given that h(x) = √(x), we substitute h(x) into g(x) to get g(h(x)).
So, g(h(x)) = h(x) - 2.
Step 2: Find the value of g(h(x))
Substitute g(h(x)) into f(x) to get f(g(h(x))).
So, f(g(h(x))) = (g(h(x)))^4 + 6.
Step 3: Calculate (g(h(x)))^4
To find the value of (g(h(x)))^4, we substitute g(h(x)) into (g(x))^4.
So, (g(h(x)))^4 = (h(x) - 2)^4.
Step 4: Expand and evaluate (h(x) - 2)^4
Expand (h(x) - 2)^4 using the binomial expansion formula or by multiplying it four times. The expanded form will look like: (h(x) - 2)*(h(x) - 2)*(h(x) - 2)*(h(x) - 2).
Finally, substitute the value of f(g(h(x))) = (g(h(x)))^4 + 6 and simplify the expression using the values you have obtained.
I hope this helps you understand how to solve the problem!