I have 6 coins two are worth 10c and forth are worth less then 10c all together they worth more the. $1.00 what coins could they be
This makes no sense.
What is this? -- forth
If you meant 2 are worth 10¢ each, and the other 4 are worth less than 10¢ each, then there is no way they could possibly be worth more than $1.00
To find out which coins could make up the given conditions, we can use deductive reasoning. Let's analyze the information provided:
1. We have a total of 6 coins.
2. Two of the coins are worth 10 cents.
3. The remaining four coins are worth less than 10 cents each.
4. The total value of all six coins is greater than $1.00.
Based on this information, we can start by assuming the four remaining coins are all worth the lowest value possible, which is 1 cent each. This assumption allows us to calculate the minimum total value of the six coins.
Minimum total value:
Two 10-cent coins = 10 cents
Four 1-cent coins = 4 cents
So, the minimum total value of the six coins is 14 cents.
However, the given information states that the total value is greater than $1.00, which is equal to 100 cents. Since the minimum total value we calculated (14 cents) is less than 100 cents, it means we need to increase the value of the four remaining coins to make the total more than 100 cents.
To do this, we can try increasing the value of each of the four remaining coins to 5 cents each. This is one possible combination among many, and there may be other valid combinations as well.
Total value:
Two 10-cent coins = 20 cents
Four 5-cent coins = 20 cents
Now, when we add up the total value, we get 40 cents. Since 40 cents is less than $1.00 (100 cents), this combination does not meet the requirement that the total value is greater than $1.00.
Therefore, we need to try a different combination. By adjusting the value of the four remaining coins, we can determine the correct combination that meets all the given conditions.