which of the following points are more than 5 vertical units away from the point (0, -2)? choose all that apply.
(6,-2)
(-8,-2)
(0,-8)
(0,4)
ITS ALREADY OVER DUE PLEASE HELP.
Thanks in advance
Points with :
Y = -2 + 6 = 4.
and Y = -2 - 6 = -8.
To find the points that are more than 5 vertical units away from the point (0, -2), we need to calculate the vertical distance between each point and the given point.
The vertical distance between two points is the difference between their y-coordinates.
Let's calculate the vertical distance for each point:
1. Point (6, -2):
Vertical distance = -2 - (-2) = 0 units
This point is 0 vertical units away from (0, -2).
2. Point (-8, -2):
Vertical distance = -2 - (-2) = 0 units
This point is also 0 vertical units away from (0, -2).
3. Point (0, -8):
Vertical distance = -8 - (-2) = -6 units
This point is more than 5 vertical units away from (0, -2).
4. Point (0, 4):
Vertical distance = 4 - (-2) = 6 units
This point is more than 5 vertical units away from (0, -2).
So, the points that are more than 5 vertical units away from (0, -2) are:
- Point (0, -8)
- Point (0, 4)
Hope this helps!
To determine which of the given points are more than 5 vertical units away from the point (0, -2), we need to measure the vertical distance between each point and the given point.
Let's calculate the vertical distance between each point and (0, -2):
1. For the point (6, -2):
The vertical distance is 0 units since the y-coordinates are the same.
2. For the point (-8, -2):
The vertical distance is 0 units since the y-coordinates are the same.
3. For the point (0, -8):
The vertical distance is |-8 - (-2)| = |-8 + 2| = |-6| = 6 units.
4. For the point (0, 4):
The vertical distance is |4 - (-2)| = |4 + 2| = |6| = 6 units.
Based on the calculations, we can see that the points (0, -8) and (0, 4) are more than 5 vertical units away from the point (0, -2). Therefore, the correct answer would be:
(0, -8) and (0, 4)