Potassium phosphide and sulfur are formed when potassium sulfide and phosphorus react.
K_2S+P -> K_3P+S
(after balancing)
= 3K_2S+2P -> 2K_3P+3S
Is this correct?
correct
Chemistry
No, the balanced equation for the reaction between potassium sulfide (K₂S) and phosphorus (P) is:
2K₂S + 2P → K₄P₂ + 2S
This balanced equation shows that two molecules of potassium sulfide react with two molecules of phosphorus to produce one molecule of potassium phosphide (K₄P₂) and two molecules of sulfur (S).
To determine if the given chemical equation is correct, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's balance the equation and check.
The given unbalanced equation is:
K₂S + P → K₃P + S
To balance the equation, we need to ensure that the number of each element is the same on both sides.
First, let's look at the potassium (K) atoms:
On the left side, we have 2 K atoms in K₂S, and on the right side, we have 3 K atoms in K₃P. To balance this, we need to multiply K₂S by 3.
Balanced so far: 3 K₂S + P → K₃P + S
Next, let's look at the sulfur (S) atoms:
On the left side, we have 1 S atom in K₂S, and on the right side, we have 1 S atom. The sulfur is already balanced.
Lastly, let's look at the phosphorus (P) atoms:
On the left side, we have 1 P atom, and on the right side, we have 1 P atom. The phosphorus is also balanced.
The balanced equation is:
3 K₂S + P → 2 K₃P + S
So, your balanced equation is correct:
3 K₂S + P → 2 K₃P + S