A golfgreen is 18m wide. Within what angle must a player hit the ball in order to land on the green from a position 215m from the green?
The angle of a cone is 35.4 degrees. Determine the diameter of the cone at a poiint on the face 22cm from the vertex.
the range of the shot depends on the velocity as well as the angle.
Maximum range is when the ball is hit at a 45° angle.
The range R = v^2/g sin2θ
So, the minimum velocity possible to land on the green is
215 <= v^2/9.8 = 233
By the angle, do you mean the angle at the vertex, or the angle the side makes with the base? If the base angle, then
Draw a side view of the cone. You can see that to find the radius, you just need to figure 22/r = tan35.4°
If the former, then r/22 = tan17.7°
To determine the angle that a player must hit the ball to land on the green, we can use trigonometry. We can use the concept of the right triangle formed by the player's position, the width of the green, and the distance from the player to the green.
Here's how we can calculate the angle:
1. First, draw a diagram to visualize the situation. Label the width of the green (18m) as the base of the right triangle and the distance from the player to the green (215m) as the hypotenuse.
2. We can use the trigonometric function called the inverse tangent (or arctan) to find the angle. The formula is:
angle = arctan(opposite/adjacent)
In this case, the opposite side is the width of the green (18m) and the adjacent side is the distance from the player to the green (215m).
3. Plug in the values into the formula:
angle = arctan(18/215)
4. Use a calculator to find the arctan of 18/215. The angle is approximately 5.85 degrees.
Therefore, a player must hit the ball at an angle of approximately 5.85 degrees to land on the green from a position 215m away.
Moving on to the question about the angle of a cone, it seems there is a mismatch of information between the question and the given details. Could you please provide more clarity or correct the details mentioned?