write the output of the segment of the program below
1 let S=0
2 For C = 1 to 5
3 let S = S+C
4 next C
5 Print S
Since your Print S is outside the For-Next loop
it gets printed only once, at the end
And since S will be set to 6 before reaching the
4 next C, where the program would check
Complete a trace chart:
S C
0 1
1 2
3 3
6 4
10 5
15
So your output is 15,
Why don't you just run these little programs and see what comes out
my system got damage......
pls how to solve this question
write the output of the segment of program below
10 READ score
20 DATA 60
30 IF score <=49 THEN
40 PRINT "you have failed"
50 ELSELF score >=50 AND score <=59 THEN
60 PRINT "you have B"
70 ELSELF score >=60 AND score <=69 THEN
80 PRINT "YOU have B"
90 ELSE
100 PRINT "YOU have A"
110 END
To determine the output of the segment of the program, let's go through each line and keep track of the value of the variable S:
1. Let S = 0: At this point, the variable S is assigned the initial value of 0.
2. For C = 1 to 5: This line initiates a loop where the variable C takes values from 1 to 5, inclusive.
3. Let S = S + C: Within the loop, the value of C is added to the current value of S and reassigned to S. So, in the first iteration, S becomes 0 + 1 = 1. In the second iteration, S becomes 1 + 2 = 3. In the third iteration, S becomes 3 + 3 = 6. In the fourth iteration, S becomes 6 + 4 = 10. Finally, in the fifth iteration, S becomes 10 + 5 = 15.
4. Next C: This line indicates the end of the loop, and the program will move to the next line.
5. Print S: The value of S, which is 15 in this case, will be printed as the output.