calculate the work done by a bricklayer who lifted cement block of mass 10kg from the floor to a height of of 2.5m (acceleration due to gravity is 9.8ms²)?
You refered to the acceleration due to gravity as 9.8m/s^2. Another way to look at this is a gravity field unit, on our earth, the gravity field operating on any mass is 9.8 Newtons/kgOf mass, or 9.8N/kg. Because we do not see gravity field strength (with our eyes), we speak often of things we can measure, like distance and time, and say g=9.8m/s^2. In fact, g is gravity field strength (ie "g", get it?), but it is equal to...not this:
<The gravitational field strength at a point is the gravitational force exerted per unit mass placed at that point. This means that the gravitational field strength, g {\displaystyle g} is equal to the force experienced by a mass of 1 kg in that gravitational field>
so work= gravity field strentth* mass moved*distance moved
= 9.8N/kg * 2.5m*10kg.
An object having mass 10 kg is raised to 3m above the ground. Calculate the workdone. (g=10)
To calculate the work done, we need to use the formula:
Work = Force × Distance × cos(θ)
Where:
Force = mass × acceleration due to gravity = 10 kg × 9.8 m/s²
Distance = height = 2.5 m
θ = angle between the force and the direction of motion (in this case, the force is vertical, so θ = 0°)
Plugging in the values, we have:
Work = (10 kg × 9.8 m/s²) × 2.5 m × cos(0°)
The cosine of 0° is equal to 1, so the equation simplifies to:
Work = (10 kg × 9.8 m/s²) × 2.5 m
Calculating further, we get:
Work = 245 Joules
Therefore, the work done by the bricklayer in lifting the cement block is 245 Joules.
To calculate the work done by the bricklayer, we can use the equation:
Work = Force × Distance
First, let's find the force required to lift the cement block. The force can be calculated using Newton's second law of motion:
Force = mass × acceleration
Given that the mass of the cement block is 10 kg and the acceleration due to gravity is 9.8 m/s², we can calculate the force as follows:
Force = 10 kg × 9.8 m/s² = 98 N
Next, we need to calculate the distance over which the force is applied. In this case, the distance is the height the cement block is lifted, which is 2.5 m.
Now we have all the values we need to calculate the work:
Work = Force × Distance
= 98 N × 2.5 m
= 245 J
Therefore, the work done by the bricklayer is 245 Joules (J).