Zidane and Shemique are looking up at their school from the playing field at the back of the school. From Zidanes point of view, the top of the school is at an angle of elevation of 43 degrees. From Shemique point of view, directly closer to the school it is 62 . The school is 27m High. How far apart are Zidane And Shemique
Tan43 = 27/X1.
X1 = 27/Tan43 = Zidane's distance from bldg.
X2 = 27/Tan62 = Shemique's distance from bldg.
d = X1 - X2 = Distance between them.
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so whats the answer
Why Cos? It's tan
nobody said anything about cos
cotangent!
To find the distance between Zidane and Shemique, we can use the concept of trigonometry. Specifically, we can use the tangent function.
Let's break down the problem:
1. From Zidane's point of view, the angle of elevation to the top of the school is 43 degrees. From this information, we can imply that Zidane is standing at the back of the school, forming a right-angled triangle with the top of the school as the vertical side and the ground as the horizontal side.
2. From Shemique's point of view, the angle of elevation to the top of the school is 62 degrees. Shemique is standing directly closer to the school, forming another right-angled triangle with the top of the school as the vertical side and the distance between them as the horizontal side.
3. We know that the height of the school is 27 meters.
To find the horizontal distance between Zidane and Shemique, we need to determine the lengths of the horizontal sides of both right-angled triangles.
First, let's calculate the side lengths of Zidane's triangle:
Let h1 be the length of the horizontal side (distance between Zidane and the school) in Zidane's triangle.
We can use the tangent function with the angle of elevation (43 degrees) and the height of the school (27m):
tan(43) = height / h1
h1 = height / tan(43)
h1 = 27 / tan(43)
h1 ≈ 27 / 0.932 = 28.99m (rounded to two decimal places)
Now let's calculate the side lengths of Shemique's triangle:
Let h2 be the length of the horizontal side (distance between Shemique and the school) in Shemique's triangle.
We can use the tangent function with the angle of elevation (62 degrees) and the height of the school (27m):
tan(62) = height / h2
h2 = height / tan(62)
h2 = 27 / tan(62)
h2 ≈ 27 / 2.323 = 11.62m (rounded to two decimal places)
Finally, to find the distance between Zidane and Shemique, we can subtract h2 from h1:
Distance = h1 - h2
Distance ≈ 28.99m - 11.62m
Distance ≈ 17.37m (rounded to two decimal places)
Therefore, Zidane and Shemique are approximately 17.37 meters apart.
Draw the diagram. It should be clear that if the distance between them is x, then
x = 27cot43° - 27cot62°
GRADE 10 ??? THIS IS GRADE 10 NOT 12
who cares what grade it is?
You taking trig or not?