a body x mass of 0.2kg moving vertically upwards has its velocity increased uniformly from 10m/s to 40m/s in just 4 sec.
neglecting air resistance, calculate the upward cervical force acting on the body
let up force = f
then
f - mg = ma
f = m(a+g)
a = change in velocity / change in time = 30/4 = 7.5
f = .2(7.5+ 9.8)
To calculate the upward net force acting on the body, you can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.
Given:
Mass (m) = 0.2 kg
Initial velocity (u) = 10 m/s
Final velocity (v) = 40 m/s
Time taken (t) = 4 sec
First, we need to calculate the acceleration (a). We can use the following equation derived from the definition of acceleration:
a = (v - u) / t
Substituting the given values:
a = (40 m/s - 10 m/s) / 4 sec
a = 30 m/s / 4 sec
a = 7.5 m/s²
Now that we have the acceleration, we can calculate the net force (F) using Newton's second law of motion:
F = m * a
Substituting the given mass:
F = 0.2 kg * 7.5 m/s²
F = 1.5 N
Therefore, the upward net force acting on the body is 1.5 Newtons.