4Fe +3O2=2Fe2O3 if the amount of ferrous is 16g the find the amount of O2 in the chemical equation
2232/160=52/a
1116/80=52/a
558/40=52/a
279/20=52/a
279×a=52×20
279×a=1040
a=1040÷279
a=3.72
1116/80=52/a
558/40=52/a
279/20=52/a
279×a=52×20
279×a=1040
a=1040÷279
a=3.72