a force of2n stretches aan elastic material by 30mm, what additional force streetched the materiald 35mm. assume that elastic limit is not exceeded.
2/30 = (2+x)/35.
70/30 = 2+x,
7/3 = 2+x,
X = 1/3 mm.
To find the additional force required to stretch the material by 35mm, we can use Hooke's Law. Hooke's Law states that the force required to stretch or compress an elastic material is directly proportional to the extension (change in length) of the material.
Given:
Initial force (F1) = 2N
Initial extension (x1) = 30mm
Additional extension (x2) = 35mm
To find the additional force (F2), we need to calculate the spring constant (k) first:
k = F1 / x1
k = 2N / 30mm
Next, we can use the spring constant to calculate the additional force (F2) using the following equation:
F2 = k * x2
F2 = (2N / 30mm) * 35mm
By simplifying the equation, we get:
F2 = 2N * 35mm / 30mm
F2 = 70N / 30
F2 ≈ 2.33N
Therefore, the additional force required to stretch the material by 35mm is approximately 2.33N.