Questions LLC
Login
or
Sign Up
Ask a New Question
Questions
Math
clog sinx+tanx
1 answer
what is "clog" ?
and what is the question?
You can
ask a new question
or
answer this question
.
Related Questions
How do I solve this?
tan^2x= 2tanxsinx My work so far: tan^2x - 2tanxsinx=0 tanx(tanx - 2sinx)=0 Then the solutions are: TanX=0
For x≠0, the slope of the tangent to y=xcosx equals zero whenever:
(a) tanx=-x (b) tanx=1/x (c) sinx=x (d) cosx=x Please help.
Simplify #3:
[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
Prove the following:
[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
Q: If y=sinx/(1+tanx), find value of x not greater than pi, corresponding to maxima or minima value of y. I have proceeded thus-
Prove:
sinx + tanx = tanx (1 + cosx) What I have so far: LS: = sinx + tanx = sinx + (sinx / cosx) = (sinx) (cosx) + sinx / cos =
Trigonometric Identities
Prove: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
Prove the following identity:
1/tanx + tanx = 1/sinxcosx I can't seem to prove it. This is my work, I must've made a mistake
1/tanx-secx+ 1/tanx+secx=-2tanx
so this is what I did: =tanx+secx+tanx-secx =(sinx/cosx)+ (1/cosx)+(sinx/cosx)-(1/cosx)
I'm only aloud to manipulate one side of the problem and the end result has to match the other side of the equation
Problem 1.