a student needed to standardize a solution of barium hydroxide.he prepared a standard solution with 0.200M of potassium hydrogen phlelete acid KHC8H4O4.this titration indicated equivalence of 27.80cm3 of Ba(OH)2 solution. what's the molar concentration of the base?
potassium hydrogen phthalate, KHP
2KHP + Ba(OH)2 ==> BaP + 2H2O
How much of 0.200 M KHP did the student use?
mol KHP = 0.200 M x L of KHP used.
mols Ba(OH)2 from the coefficient = 1/2 mols KHP from above.
Then M Ba(OH)2 = mols Ba(OH)2/0.02780 = ?
To find the molar concentration of the base (Ba(OH)2), we can use the equation:
M (KHC8H4O4) x V (KHC8H4O4) = M (Ba(OH)2) x V (Ba(OH)2)
Where:
M (KHC8H4O4) is the molar concentration of potassium hydrogen phthalate (given as 0.200 M)
V (KHC8H4O4) is the volume of potassium hydrogen phthalate used (unknown)
M (Ba(OH)2) is the molar concentration of barium hydroxide (unknown)
V (Ba(OH)2) is the volume of barium hydroxide used (given as 27.80 cm3)
Plugging in the values:
0.200 M x V (KHC8H4O4) = M (Ba(OH)2) x 27.80 cm3
To isolate M (Ba(OH)2), we divide both sides of the equation by 27.80 cm3:
M (Ba(OH)2) = (0.200 M x V (KHC8H4O4)) / 27.80 cm3
However, we still need to know the volume of potassium hydrogen phthalate used (V (KHC8H4O4)) to determine the molar concentration of barium hydroxide.
Please provide the volume of potassium hydrogen phthalate used in the titration, and I can calculate the molar concentration of barium hydroxide for you.
To find the molar concentration of the barium hydroxide (Ba(OH)2) solution, we can use the concept of stoichiometry and the volume of the standardized acid solution used in the titration.
Here's how you can calculate the molar concentration of the base:
1. Write down the balanced chemical equation for the reaction between potassium hydrogen phthalate (KHC8H4O4) and barium hydroxide (Ba(OH)2):
KHC8H4O4 + Ba(OH)2 -> K2C8H4O4 + 2H2O
2. Identify the stoichiometric ratio between KHC8H4O4 and Ba(OH)2 from the balanced equation. In this case, it is 1:1, meaning 1 mole of KHC8H4O4 reacts with 1 mole of Ba(OH)2.
3. Determine the number of moles of KHC8H4O4 used in the titration by using the formula:
Moles = Molarity × Volume (in liters)
Given that the volume used is 0.02780 L (converted from cm3 to L) and the molarity is 0.200 M, you can calculate the moles of KHC8H4O4.
Moles of KHC8H4O4 = 0.200 M × 0.02780 L
4. Since the stoichiometric ratio between KHC8H4O4 and Ba(OH)2 is 1:1, the number of moles of Ba(OH)2 present in the solution is also the same as the number of moles of KHC8H4O4.
5. Finally, calculate the molar concentration of the Ba(OH)2 solution by dividing the moles of Ba(OH)2 by the final volume in liters:
Molarity of Ba(OH)2 = Moles of Ba(OH)2 / Volume (in liters)
The molar concentration of the barium hydroxide (Ba(OH)2) solution can be determined using the given information and the steps outlined above.