if angie rolls a fair number cube 66 times about how many times will she roll a number that is odd and less than 5
what is this
2/6 = 1/3
Sorry I goofed. Either-or probabilities are found by adding the individual probabilities.
1/3 * 66 = ?
To determine the approximate number of times Angie will roll an odd number less than 5, we can use probability.
Step 1: Identify the sample space.
The sample space consists of all the possible outcomes when rolling a number cube. Since a fair number cube has six sides numbered 1 to 6, the sample space contains numbers from 1 to 6.
Step 2: Identify the favorable outcomes.
In this case, the favorable outcomes are odd numbers less than 5. So, the favorable outcomes are: 1 and 3.
Step 3: Determine the probability of rolling a favorable outcome.
The probability of rolling each favorable outcome is 1/6, as there is one favorable outcome out of six possible outcomes (numbers from 1 to 6). Thus, the probability of rolling an odd number less than 5 is 2/6 = 1/3.
Step 4: Calculate the approximate number of favorable outcomes.
To find the approximate number of times Angie will roll a favorable outcome, multiply the number of trials (66 rolls) by the probability of a favorable outcome (1/3).
Approximate number of rolls = 66 * (1/3)
Approximate number of rolls = 22
Therefore, Angie will roll an odd number less than 5 approximately 22 times out of 66 rolls.
You are talking about the probability of getting a 1 or 3 = 1/6 * 1/6 = 1/36.
Take it from there.