In what state is iron II Tetra OXO sulphate six heptahydrate if heated to110 degree centigrade
You post is garbled. I have no idea what you mean.
Heating Iron(II)Sulfate Heptahydrate (Cuprian Melanterite)* to 110⁰C will only decompose the hydrate into the anhydrate crystalline solid Iron(II) Sulfate and water vapor. Decomposition of the FeSO₄(s) occurs ~680⁰C into Iron(III) Oxide and a mix of SO₂(g) and SO₃(g).
FeSO₄∙7H₂O(s) + Δ(110⁰C) => FeSO₂(s) + 7H₂O(g)
FeSO₂(s) + Δ(680⁰C) => Fe₂O₃(s) + SO₂(g) + SO(g)
………………………………………………………………………………
* h ttps://en.wikipedia.org/wiki/Melanterite
To determine the state of iron II Tetra OXO sulphate six heptahydrate when heated to 110 degrees Celsius (Centigrade), we need to understand the concept of hydrates and their behavior under different conditions.
Hydrates are compounds that contain a specific number of water molecules integrated into their crystalline structure. Heating a hydrate can cause the water molecules to be released, resulting in a change of state for the compound.
In this case, iron II Tetra OXO sulphate six heptahydrate is a specific hydrate in which six water molecules are associated with each molecule of the compound. When heated, these water molecules can be driven off, leading to a change in the state of the compound.
To determine the state of the compound after heating, we need to know its original state and the effect heating has on that state. Without this information, it is difficult to provide an exact answer.
However, based on our understanding of hydrates, most hydrates lose their water molecules when heated, resulting in a change from a solid state to either a liquid or gas state, depending on the specific compound. So, it is likely that iron II Tetra OXO sulphate six heptahydrate would undergo a phase change and transition to a different state when heated to 110 degrees Celsius.
To precisely determine the state change and other properties, it would be advisable to consult specific scientific literature or reference material on that compound.