A rectangle with area 60 ft^2 has a length 7.7 ft longer than its width. What is the perimeter of the rectangle, in ft?
w(w+7.7) = 60
solve that to get w. Then the perimeter
p = 2(w + w+7.7)
solve that to get w. Then the perimeter
p = 2(w + w+7.7)