chemistry

can anyone explain how to do this problem?

At 673 K, the equilibrium constant for the
reaction
2 HI(g) ⇀↽ H2(g) + I2(g)
is Kc = 0.0200. If 0.5 mol of HI is placed in
a 2.00 liter container and heated to 673 K,
what concentration of H2 will be present at
equilibrium?
Answer in units of M.

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  1. (HI) = 0.5mol/2L = 0.25 M
    ................. 2HI(g) ⇀↽ H2(g) + I2(g)
    I..................0.25M.........0...........0
    C,,,,,,,,,,,,,,,,,,-2x.............x............x
    E,,,,,,,,,,,,,9,25-x..............x............x

    Kc = (H2)(I2)/(HI)^2
    Plug in the E line and solve for x = (H2) = (I2)
    Post your work if you get stuck.

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    DrBob222

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