the nth term of a sequence is 3(n+5) which is the first term to be larger than 100?
so, just solve for n in
3(n+5) > 100
n+5 > 33.3
n > 28.3
so, n=29
...
To find the first term of the sequence that is larger than 100, we can substitute values for n until we find a term that satisfies the condition.
The nth term of the sequence is given by the formula: 3(n+5). To find the first term larger than 100, we need to solve the inequality:
3(n+5) > 100
Let's simplify this equation:
3n + 15 > 100
Now, subtract 15 from both sides of the inequality:
3n > 85
To isolate n, divide both sides of the inequality by 3:
n > 85/3
Now we know that n must be greater than 85/3 or approximately 28.33.
Since n represents the position in the sequence, it must be a whole number. Therefore, the first value of n that makes the term larger than 100 is n = 29.
To find the first term, substitute n = 29 into the formula:
3(29+5) = 3(34) = 102
Therefore, the first term of the sequence that is larger than 100 is 102.