What are the solutions from 0 to 360 degrees?
2 sin^2 x - 1 = 0
note that this is just
-cos(2x) = 0
cos(2x) = 0 when 2x = 90° or 270° + k*360°
so, x = 45°, 135°, 225°, 315°
2 sin^2 x - 1 = 0
-cos(2x) = 0
cos(2x) = 0 when 2x = 90° or 270° + k*360°
so, x = 45°, 135°, 225°, 315°