A photocell shows photoelectric effect when green light shines on it. Which of the following is correct if a green light is replaced by a blue light?
Electron emission would get stopped.
Electrons are emitted with more velocity.
Electrons are emitted with less velocity.
Electrons are emitted with same velocity.
a blue photon is higher frequency, and therefore higher energy, than green.
a green photon has enough energy to shake an electron use
any extra energy makes the electron go faster
so
more velocity
Thank you
To determine the correct answer, we need to understand the photoelectric effect and how it is influenced by different colors of light.
The photoelectric effect is the phenomenon in which electrons are emitted from a material surface when it is exposed to light. The energy of the incident photons (light particles) plays a crucial role in this process.
According to the photoelectric effect, for electrons to be emitted from a material surface, the energy of the incident photons must be equal to or greater than the work function of the material. The work function is the minimum energy required to remove an electron from the surface of the material.
Now, coming to the given question, if a green light is replaced by a blue light, we need to compare the energy of the photons in both cases:
- Green light has a longer wavelength and less energy compared to blue light.
- Blue light has a shorter wavelength and higher energy compared to green light.
Since the energy of blue light is higher than that of green light, it means that the photons of blue light have more energy. As a result, if a photocell is exposed to blue light, the electrons emitted would have more energy (higher velocity) compared to the electrons emitted when exposed to green light.
Therefore, the correct answer is:
- Electrons are emitted with more velocity.