# physics

an object of mass 10kg is whirled round in a horizontal circle of radius 4metres by a revolving string which is inclined to vertical. if the uniform speed of the object is 5metres per second. 1. calculate the tension in the string. 2. the angle of
of the string to the vertical.

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1. horizontal length: 4sinTheta
horizontal force= 10*v^2/r= 10*(5/4sinTheta)^2
vertical force= 10*9.8

TanTheta= 10*9.8/(5/4sinTheta)^2
if the angles are small, then tanTheta=sinTheta
TanTheta=98*16Tan^2Theta/25
or 1/tanTheta=98*16/25
tanTheta= = 0.0159438776
Theta= .91 deg

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bobpursley

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