1) consider two charges q1 =3 uc and q2=-2 uc,
a) state whether the electric force between these charges is attractive ore repulsive
b) what happens to the electric force if the distance between the charges is double (multiplied by two).
2) if the current through a resistor is 5mA. how many coulombs of charge flow through this resistor in one minute?
The attract, if distance is doubled, attraction is 1/4th what it was.
1) a) To determine whether the electric force between two charges is attractive or repulsive, we need to consider the types of charges involved. Like charges (charges with the same sign) repel each other, while opposite charges (charges with different signs) attract each other.
In this case, q1 is positive (3 uc) and q2 is negative (-2 uc). Since they have opposite signs, the electric force between them will be attractive.
b) If the distance between the charges is doubled, the electric force between them will change. The electric force between two charges is inversely proportional to the square of the distance between them, according to Coulomb's law. So, if the distance is multiplied by two, the electric force will decrease by a factor of four (2 squared).
2) To calculate the number of coulombs of charge that flow through a resistor in one minute, we need to know the current and time.
Given that the current through the resistor is 5 mA (milliamperes), we need to convert it to amperes (A) since the unit of charge is coulombs (C).
1 A = 1000 mA
Therefore, the current in amperes is:
5 mA = 5/1000 A = 0.005 A
Now, we can multiply the current by the time to get the charge:
Charge = Current x Time
Charge = 0.005 A x 1 minute
Since 1 minute is 60 seconds, we should convert it to seconds:
Charge = 0.005 A x 60 seconds
Now, we can compute the charge:
Charge = 0.005 A x 60 s = 0.3 C
Therefore, 0.3 coulombs of charge flow through the resistor in one minute.