A cylindrical swimming pool has a diameter of 16 feet and a height of 4 feet. About how many gallons of water can the pool contain? Round your answer to the nearest whole number. (1 ft³ ≈ 7.5 gal)
To the nearest whole number, the pool can hold
gallons of water.
which way is down? the flat bottom of the cylinder?
If so, volume=height*PI*radius^2*7.5ga/ft^3
To find out how many gallons of water the cylindrical swimming pool can contain, we need to calculate the volume of the pool and then convert it to gallons.
The formula for the volume of a cylinder is V = πr²h, where V is the volume, r is the radius, and h is the height.
Given that the diameter of the pool is 16 feet, we can determine the radius by dividing the diameter by 2:
r = 16 ft ÷ 2 = 8 ft
We also know that the height of the pool is 4 feet.
Now we can plug these values into the formula to find the volume:
V = π(8 ft)²(4 ft)
To make the calculation, we'll need the value of π. Let's use an approximation of π = 3.14:
V ≈ 3.14 × 8 ft × 8 ft × 4 ft
Calculating this, we find:
V ≈ 3.14 × 64 ft² × 4 ft
V ≈ 805.76 ft³
Finally, we can convert this volume to gallons by multiplying it by the conversion factor of 7.5 gal per 1 ft³:
volume in gallons = 805.76 ft³ × 7.5 gal / 1 ft³
Calculating this, we get:
volume in gallons ≈ 6042.0 gal
Rounding this figure to the nearest whole number, the pool can hold approximately 6042 gallons of water.