Factor by identifying a common factor in each term.
g) 6xy2 = (3x) (?)
h) 25a3b2 = (5a2b2) (?)
i) 6x + 6y + 6p
need help please ?
g) 6xy^2 = (3x) (?)
6xy^2 = 3*2*x*y^2
Now, the commutative property of multiplication says you can rearraneg those factors as you like. So, you can also write it as
3*x*2*y^2 = (3x)(2y^2)
h) 25a^3b^2 = (5a^2b^2) (5a)
i) 6x + 6y + 6p = 6(x+y+p)
because of the distributive property
g. 6xy^2 = 3x.
6xy^2 - 3x = 0,
3x(2y^2 - 1) = 0.
h. 25a^3b^2 = 5a^2b^2.
25a^3b^2 - 5a^2b^2 = 0,
5a^2b^2(5a - 1) = 0.
I. 6x + 6y + 6p.
6(x + y + p).
Sure, I can help you with that!
g) To factor 6xy^2, we need to identify a common factor in each term. In this case, the common factor is 3x. So, we can write:
6xy^2 = 3x * (2y^2)
Therefore, the factored form of 6xy^2 is (3x)(2y^2).
h) Similarly, to factor 25a^3b^2, we can identify the common factor, which is 5a^2b^2. Thus, we can write:
25a^3b^2 = 5a^2b^2 * (5ab)
So, the factored form of 25a^3b^2 is (5a^2b^2)(5ab).
i) The expression 6x + 6y + 6p has a common factor of 6. So, we can factor it as:
6x + 6y + 6p = 6(x + y + p)
Therefore, the factored form of the expression 6x + 6y + 6p is 6(x + y + p).
I hope this helps! Let me know if you have any further questions.
Sure! Let's go through each problem step by step.
g) To factor 6xy2, we need to identify a common factor in each term. In this case, the common factor is 3x. We can factor it out by dividing each term by 3x.
6xy2 = (3x)(2y2)
So, the factored form of 6xy2 is (3x)(2y2).
h) Similarly, to factor 25a3b2, we need to identify a common factor in each term. In this case, the common factor is 5a2b2. Divide each term by 5a2b2.
25a3b2 = (5a2b2)(5ab)
So, the factored form of 25a3b2 is (5a2b2)(5ab).
i) To factor 6x + 6y + 6p, we need to identify a common factor in each term. In this case, the common factor is 6. Divide each term by 6.
6x + 6y + 6p = 6(x + y + p)
So, the factored form of 6x + 6y + 6p is 6(x + y + p).
I hope this helps! Let me know if you have any other questions.