each pail of plaster covers 90 square feet of ceiling. what is the least number of pails of plaster you would need to buy to cover the ceiling of a square room with walls 14 feet long?

A. 5 pails
B. 6 pails
C. 4 pails
D. 3 pails I think it is B am I right?

3 pailz

To determine the least number of pails of plaster you would need to cover the ceiling of a square room with walls 14 feet long, we can follow these steps:

1. Calculate the area of the ceiling: Since the room is square, the length of one side of the square room is 14 feet. To find the area, we can square the length of one side: 14 * 14 = 196 square feet.

2. Determine the number of pails needed: Each pail of plaster covers 90 square feet. To find the least number of pails needed, we can divide the area of the ceiling by the coverage of each pail: 196 / 90 ≈ 2.18.

3. Round up to the nearest whole number: Since you cannot purchase a fraction of a pail, we need to round up. So, even though 2.18 pails would technically cover the ceiling, we would need to buy at least 3 pails to cover the entire area.

Therefore, the correct answer is D. 3 pails, not option B. 6 pails.

14^2 = ?

? / 90 = !