a load of 20N gives an extension of 2.04cm in a wire which obeys hookes law. what is the extension produce by a load of 80N
what is 2.04cm * 80/20 ?
Ext. = 80N * 2.04cm/20N. = 80 * 2.04/20 = cm.
To find the extension produced by a load of 80N, we need to use Hooke's Law, which states that the extension of a spring or wire is directly proportional to the applied force.
Hooke's Law can be written as:
F = k * x
Where:
F is the applied force
k is the spring constant (a measure of how stiff or springy the wire is)
x is the extension or deformation produced
In our scenario, we have a load of 20N that produces an extension of 2.04cm. Let's use this information to find the value of k.
Rearrange the equation to solve for k:
k = F / x
Substitute the values:
k = 20N / 2.04cm
First, let's convert the extension from centimeters to meters (as the SI unit of force is Newtons and length is in meters):
k = 20N / (2.04cm / 100cm/1m)
Simplifying:
k = 20N / 0.0204m
k = 980.39 N/m
Now that we know the value of k, we can use it to find the extension produced by a load of 80N.
Rearrange the equation to solve for x:
x = F / k
Substitute the values:
x = 80N / 980.39 N/m
x ≈ 0.0816 m
So, a load of 80N will produce an extension of approximately 0.0816 meters (or 8.16 cm) in the wire.