the man spend two seventh of his pay and left him with $210 how much money he have
Nonsense.
He have $210.
If you want to know how much money he started with then "Let x represent the total amount"
Now 2/7 is gone, so 5/7 is still there (and this is $210)
x(5/7)= 210
Now re-arrange to get x alone : )
that is, multiply both sides by 7/5
x = his original amount : )
He had $X.
x - (2/7)x = (5/7)x left.
(5/7)x = $210.
5x/7 = 210,
5x = 1470,
X =
To find out how much money the man has, we need to reverse the process of him spending two-sevenths of his pay and being left with $210.
Let's start by representing the man's pay as 'x'. Since he spent two-sevenths of his pay, this would be equivalent to subtracting 2/7 of his pay from the original amount:
Amount left = x - (2/7)x
Now we know that the amount left is $210, so we can set up the equation:
210 = x - (2/7)x
To solve this equation, we can simplify it by finding a common denominator:
210 = (7/7)x - (2/7)x
Combining like terms:
210 = (5/7)x
To isolate x, we need to divide both sides of the equation by (5/7):
210 / (5/7) = x
To divide fractions, we multiply by the reciprocal:
210 * (7/5) = x
Now, simplifying:
(210 * 7) / 5 = x
1470 / 5 = x
294 = x
Therefore, the man originally had $294.