You toss a coin 3 times. Find these probabilities:



P(all 3 are heads)
P(exactly 2 T's)
P(exactly 2 T's given that first toss is T)

Woahhh! This looks like a Home-Work-Dump or a test

I did one of them for you, now you show some work with answers
so we can evaluate them. If not, show us where your difficulty is.
Nobody is just going to do your work for you.

its homework i have like 50 questions and these are just the ones i am struggling with just had surgery last week and for some reason i am just not able to remember this information at the moment im actually taking notes from the help i get with them ow to try and jog my memory

when it comes to getting all three as heads i believe it would be 1/2*1/2*1/2=1/8

Ok, let's look at this one: toss a coin 3 times

How many outcomes, perhaps list them.
How many of those look like HHH ?
So what is prob(3 heads) ?

Also tell me what you get for the other 2 questions.

you have a 50/50 or 1/2 chance on each to get the heads

i think its 1/4 for the 2nd question and im still working on the 3rd

To find the probabilities, we need to know the total number of possible outcomes and the number of favorable outcomes for each case.

1) P(all 3 are heads):

The total number of possible outcomes when tossing a coin 3 times is 2^3 = 8 (since each coin flip has 2 possibilities: heads or tails).

The number of favorable outcomes for this case is 1 (all 3 are heads).

So, P(all 3 are heads) = number of favorable outcomes / total number of possible outcomes = 1/8 = 0.125 or 12.5%.

2) P(exactly 2 T's):

To find the number of favorable outcomes for this case, we need to consider all the possible ways to get exactly 2 tails when tossing a coin 3 times:

- TTH
- THT
- HTT

There are 3 favorable outcomes.

So, P(exactly 2 T's) = 3/8 = 0.375 or 37.5%.

3) P(exactly 2 T's given that the first toss is T):

Since we know that the first toss is tails, we now have 2 remaining tosses.

The total number of possible outcomes for the remaining 2 tosses is 2^2 = 4.

The number of favorable outcomes is still 3 (TTH, THT, HTT), as we need exactly 2 tails in the remaining 2 tosses.

So, P(exactly 2 T's given that the first toss is T) = 3/4 = 0.75 or 75%.