What happens when you dissolve CO2 (g) into NaOH (aq). (explain using net ionic equation)
2NaOH + CO2 ==> Na2CO3 + H2O
2OH^-(aq) + CO2(g) ==> CO3^2-(aq) + H2O(l)
This is a 2-step process...
1. Carbon dioxide and water react to make carbonic acid.
CO2(aq)+H2O(l)⟶H2CO3(aq)
Carbonic acid reacts with hydroxide ions (acid/base metathesis rxn) to make sodium bicarbonate and water.
2. H2CO3(aq)+NaOH(aq)⟶NaHCO3(aq)+H2O(l)
Ionic Equation => H2CO3(aq) + Na^+(aq) + OH^-(aq) ==> Na^+(aq) + HCO3^-(aq) + H2O(l)
Net Ionic Equation (Na^+(aq) is spectator ion):
H2CO3(aq) + OH^-(aq) ==> HCO3^-(aq) + H2O(l)
When you dissolve carbon dioxide (CO2) gas into an aqueous solution of sodium hydroxide (NaOH), the following reaction occurs:
CO2 (g) + 2NaOH (aq) → Na2CO3 (aq) + H2O (l)
This balanced chemical equation represents the overall reaction. However, to show only the species that undergo a chemical change, we can write the net ionic equation by separating the soluble compounds into their individual ions:
CO2 (g) + 2Na+ (aq) + 2OH- (aq) → Na2CO3 (aq) + H2O (l)
In this net ionic equation, CO2 reacts with two sodium ions (Na+) and two hydroxide ions (OH-) to form one molecule of sodium carbonate (Na2CO3) and one molecule of water (H2O).
To understand what happens when CO2 (g) is dissolved into NaOH (aq), we need to write the net ionic equation for the reaction.
First, let's write the balanced chemical equation for the reaction:
CO2 (g) + 2 NaOH (aq) -> Na2CO3 (aq) + H2O (l)
In this equation, carbon dioxide (CO2) reacts with sodium hydroxide (NaOH) to produce sodium carbonate (Na2CO3) and water (H2O).
Now, let's write the net ionic equation for the reaction by removing the spectator ions (ions that do not participate in the reaction):
CO2 (g) + 2 OH- (aq) -> CO32- (aq) + H2O (l)
In the net ionic equation, we can see that carbon dioxide reacts with hydroxide ions (OH-) to form carbonate ions (CO32-) and water. The sodium ions (Na+) remain unchanged and are spectator ions in this reaction.
Overall, when carbon dioxide is dissolved in sodium hydroxide, it reacts to form sodium carbonate and water, as shown by the net ionic equation.