How many atom of oxygen are present in 8.8g of carbon(iv)oxide
Moles CO2 = 8.8-g CO2/44g/mole CO2 = 0.20 mole CO2 x 6.02E23 molecules CO2/mole = 1.204E23 molecules CO2 in the 8.8-gram sample.
#atoms Oxy per CO2 molecule = 2
Therefore, #oxy atoms in 8.8-g CO2 = 1.204E23 molecules CO2 x 2 oxy molecules/CO2 molecule = 2.408E23 oxy atoms in the 8.8-g sample of CO2.
ion
To find the number of atoms of oxygen present in 8.8g of carbon(iv)oxide, we need to use the concept of moles and atomic masses.
1. First, determine the molar mass of carbon(iv)oxide (CO2). The atomic mass of carbon (C) is approximately 12.01 g/mol, and the atomic mass of oxygen (O) is approximately 16.00 g/mol. Since there are two oxygen atoms in CO2, we calculate the molar mass as:
Molar mass of CO2 = (2 * Atomic mass of O) + Atomic mass of C
= (2 * 16.00 g/mol) + 12.01 g/mol
= 32.00 g/mol + 12.01 g/mol
= 44.01 g/mol
2. Next, calculate the number of moles of carbon(iv)oxide. To do this, divide the mass given (8.8g) by the molar mass of CO2:
Number of moles = Mass / Molar mass
= 8.8g / 44.01 g/mol
≈ 0.1997 mol (rounded to four decimal places)
3. Finally, determine the number of oxygen atoms present. Since there are two oxygen atoms in one mole of CO2, we multiply the number of moles by Avogadro's number (6.022 x 10^23) to find the number of atoms:
Number of oxygen atoms = Number of moles * Avogadro's number
= 0.1997 mol * 6.022 x 10^23 atoms/mol
= 1.202 x 10^23 atoms (rounded to three significant figures)
Therefore, there are approximately 1.202 x 10^23 atoms of oxygen present in 8.8g of carbon(iv)oxide.