a uniform metre rule of Mass 150g is pivoted at 60cm Mark.cal the mass which when hung at the 85cm Mark will balance horizontally
CM=ACM
50-60=10
85-60=25
10×150=1500
1500=25
=60g
no idea
Calculating moments about the piviot point:
150*10cm-M*25cm=0
M=1500/25 grams
To find the mass that will balance the uniform meter rule when hung at the 85cm mark, we can use the principle of moments. The principle of moments states that for an object to be in rotational equilibrium, the total sum of the clockwise moments has to be equal to the total sum of the counterclockwise moments.
First, let's calculate the moment caused by the mass of the meter rule itself. Since the meter rule is balanced at the 60cm mark, we can consider the 60cm mark as the pivot point. The moment caused by the mass of the meter rule would be given by:
Moment of meter rule = Mass of meter rule * Distance from the pivot point
= 150g * 60cm
Next, we need to determine the mass that will be hung at the 85cm mark. Let's call this mass M. The moment caused by this mass would be:
Moment of M = M * Distance from the pivot point
= M * 85cm
Since the meter rule is balanced, the moment caused by the meter rule itself will be equal to the moment caused by the mass at the 85cm mark. Therefore, we can set up the equation:
150g * 60cm = M * 85cm
Now, let's solve for M:
150g * 60cm = M * 85cm
To simplify the units, we can convert grams to kilograms and centimeters to meters:
0.15kg * 0.6m = M * 0.85m
Multiplying both sides of the equation by 0.85:
0.15kg * 0.6m / 0.85 = M
Simplifying this equation gives:
M ≈ 0.127 kg
Therefore, the mass that needs to be hung at the 85cm mark to balance the meter rule horizontally is approximately 0.127 kg or 127 grams.