What is the mass of sodium needed to make 2 g of sodium oxide (4Na + O2 → 2Na2O)?
Ar values: O = 16, Na = 23.
please help im really struggling. also please try to explain it to the simplest form because i really don't understand.
i got 1.48
but how?
i think that is correct but i dont know how to get to that
To calculate the mass of sodium needed to make 2 g of sodium oxide (Na2O), we need to use the balanced equation provided:
4Na + O2 → 2Na2O
First, we need to find the molar mass of sodium oxide (Na2O) by using the atomic masses given in the problem.
Molar mass of Na2O = (2 x atomic mass of Na) + (1 x atomic mass of O)
= (2 x 23) + (1 x 16)
= 46 + 16
= 62 g/mol
Since the molar mass of Na2O is 62 g/mol, we can now calculate the number of moles of Na2O produced from 2 g of Na2O using the formula:
Number of moles = Mass / Molar mass
Number of moles of Na2O = 2 g / 62 g/mol
≈ 0.032 mol
According to the balanced equation, 4 moles of sodium (Na) is required to produce 2 moles of sodium oxide (Na2O).
So, the number of moles of sodium (Na) required to produce 0.032 mol of Na2O is:
Number of moles of Na = (4 mol Na / 2 mol Na2O) x 0.032 mol Na2O
= 0.064 mol Na
Finally, to find the mass of sodium (Na) required, we can use the equation:
Mass = Number of moles x Molar mass
Mass of Na = 0.064 mol x 23 g/mol
= 1.472 g
Therefore, to make 2 g of sodium oxide (Na2O), you would need approximately 1.472 g of sodium (Na).