The sum of 4 consecutive integers is t. In terms of t, find the smallest of the four integers
x + ( x+1) + (x+2) + (x+3) = t.
4x + 6 = t,
4x = t-6,
X = (t-6)/4.
you have an arithmetic progression with
a = x
d = 1
n = 4
so, using your sum formula,
4/2 (2x + 3) = t
x = (t-6)/4
Let's represent the smallest of the four consecutive integers as x.
Since the four integers are consecutive, the second integer would be x + 1, the third integer would be x + 2, and the fourth integer would be x + 3.
Using this information, we can write the equation for the sum of the four integers:
x + (x + 1) + (x + 2) + (x + 3) = t
To simplify this equation, we combine like terms on the left-hand side:
4x + 6 = t
To isolate the variable x, we subtract 6 from both sides of the equation:
4x = t - 6
Finally, we divide both sides of the equation by 4 to solve for x:
x = (t - 6)/4
Therefore, the smallest of the four integers in terms of t is (t - 6)/4.
To find the smallest of the four consecutive integers, let's assume that the first integer is x.
Since the four integers are consecutive, the second integer would be x + 1, the third integer would be x + 2, and the fourth integer would be x + 3.
The sum of these four consecutive integers would be:
x + (x + 1) + (x + 2) + (x + 3) = t
Now, let's simplify the equation:
4x + 6 = t
To find the value of x in terms of t, we'll subtract 6 from both sides of the equation:
4x = t - 6
Finally, to find the smallest integer, substitute the value of x back into the equation:
x = (t - 6) / 4
Therefore, the smallest of the four consecutive integers in terms of t would be (t - 6) / 4.