If a wire has a resistance, 1.32ohms,the length of 110cm,and an area of cross sectional of 0.00415cm,find the resistivity of the material of which it is made?
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To find the resistivity of the material, we need to use the formula:
R = (ρ * L) / A
Where:
R = Resistance of the wire
ρ = Resistivity of the material
L = Length of the wire
A = Cross-sectional area of the wire
We have the values for R, L, and A. We can rearrange the formula to solve for ρ:
ρ = (R * A) / L
Now let's substitute the values into the equation:
ρ = (1.32 Ω * 0.00415 cm) / 110 cm
First, we need to convert the units so that they are consistent. We'll convert the resistance from ohms to ohm-meter:
1 meter = 100 cm
So, 1 Ω = 1 ohm-meter
Now, let's rewrite the equation after converting the units:
ρ = (1.32 ohm-meter * 0.00415 cm) / 110 cm
Next, we simplify the equation:
ρ = (1.32 * 0.00415) / 110
ρ = 0.0050172 / 110
Finally, we calculate the value of resistivity:
ρ ≈ 0.00004561 ohm-meter (rounded to five decimal places)
Therefore, the resistivity of the material of the wire is approximately 0.00004561 ohm-meter.
resisitivity= resistance*area/length.
Now your cross sectional area you listed as 0.00415cm. Is this 0.00415cm^2?
resistivity should be in ohm-meter, so we will make that conversion later.
resistivity=resistance*area/length= 120ohm*.00415cm^2/120cm
now to make the change from cm to m..
=120ohm*.00415cm^2/120cm * 1m/100cm
that should do it.