Calculate the percentage of mass of all the component elements in sodiumtrioxonitrate(VI)
molar mass of sodium nitrate is 85grams
atomic mass Na is 23g
atomic mass O is 16
NaNO3
Na%=23/85
N%=14/85
O%=16*3/85
There is no such thing as sodium trioxonitrate(VI).
%Na = [(mass Na/mass NaNO3)]*100 = ?
The others are done the same way
To calculate the percentage of mass of all the component elements in sodiumtrioxonitrate(VI) (also known as sodium nitrate), we need to know the chemical formula of the compound, which indicates the type and number of atoms present.
The chemical formula of sodium nitrate is NaNO3. It consists of one sodium (Na) atom, one nitrogen (N) atom, and three oxygen (O) atoms.
To calculate the percentage of mass of each element, we need to find the molar mass of each element and the molar mass of the entire compound.
1. Sodium (Na):
The atomic mass of sodium (Na) is approximately 22.99 g/mol. Since there is only one sodium atom in the formula, the contribution of sodium to the total mass is:
Mass of sodium = 1 * 22.99 g/mol
2. Nitrogen (N):
The atomic mass of nitrogen (N) is approximately 14.01 g/mol. There is one nitrogen atom in the formula, so the contribution of nitrogen to the total mass is:
Mass of nitrogen = 1 * 14.01 g/mol
3. Oxygen (O):
The atomic mass of oxygen (O) is approximately 16.00 g/mol. Since there are three oxygen atoms in the formula, the contribution of oxygen to the total mass is:
Mass of oxygen = 3 * 16.00 g/mol
To calculate the molar mass of the entire compound, we sum up the individual contributions:
Molar mass of NaNO3 = Mass of sodium + Mass of nitrogen + Mass of oxygen
Finally, to find the percentage of each element's mass in the compound, we divide the individual contribution by the molar mass of the compound and multiply by 100:
Percentage of mass of sodium = (Mass of sodium / Molar mass of NaNO3) * 100
Percentage of mass of nitrogen = (Mass of nitrogen / Molar mass of NaNO3) * 100
Percentage of mass of oxygen = (Mass of oxygen / Molar mass of NaNO3) * 100