What are the solutions to the quadratic equation 3(x+5)(x−7)=0?

Solving an equation whose product is zero is by setting each factor to zero.

3 ( x + 5 ) ( x − 7) = 0

Divide both sides by 3

( x + 5 ) ( x − 7) = 0

x + 5 = 0 ⇒ x = - 5

x - 7 = 0 ⇒ x = 7

The solutions are x = - 5 and x = 7

Bosnian's approach is much better.

To find the solutions to the quadratic equation 3(x+5)(x−7)=0, we can use the zero product property. The zero product property states that if a product of factors is equal to zero, then one or more of the factors must be equal to zero.

So, we set each factor equal to zero and solve for x:

x + 5 = 0
x = -5

x - 7 = 0
x = 7

Therefore, the solutions to the quadratic equation 3(x+5)(x−7)=0 are x = -5 and x = 7.

One way to solve is to expand the equation and then use the quadratic equation to solve for x.

So the answers 5?